(d+2)-36=2+6(1-d)

Solution for (d+2)-36=2+6(1-d) equation:

(d+2)-36=2+6(1-d)

We move all terms to the left:

(d+2)-36-(2+6(1-d))=0

We add all the numbers together, and all the variables

(d+2)-(2+6(-1d+1))-36=0

We get rid of parentheses

d-(2+6(-1d+1))+2-36=0


We calculate terms in parentheses: -(2+6(-1d+1)), so:

2+6(-1d+1)

determiningTheFunctionDomain
6(-1d+1)+2

We multiply parentheses

-6d+6+2

We add all the numbers together, and all the variables

-6d+8

Back to the equation:

-(-6d+8)


We add all the numbers together, and all the variables

d-(-6d+8)-34=0

We get rid of parentheses

d+6d-8-34=0

We add all the numbers together, and all the variables

7d-42=0

We move all terms containing d to the left, all other terms to the right

7d=42

d=42/7

d=6