(d-1)(d+5)=

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Solution for (d-1)(d+5)= equation:


Simplifying
(d + -1)(d + 5) = 0

Reorder the terms:
(-1 + d)(d + 5) = 0

Reorder the terms:
(-1 + d)(5 + d) = 0

Multiply (-1 + d) * (5 + d)
(-1(5 + d) + d(5 + d)) = 0
((5 * -1 + d * -1) + d(5 + d)) = 0
((-5 + -1d) + d(5 + d)) = 0
(-5 + -1d + (5 * d + d * d)) = 0
(-5 + -1d + (5d + d2)) = 0

Combine like terms: -1d + 5d = 4d
(-5 + 4d + d2) = 0

Solving
-5 + 4d + d2 = 0

Solving for variable 'd'.

Factor a trinomial.
(-5 + -1d)(1 + -1d) = 0

Subproblem 1

Set the factor '(-5 + -1d)' equal to zero and attempt to solve: Simplifying -5 + -1d = 0 Solving -5 + -1d = 0 Move all terms containing d to the left, all other terms to the right. Add '5' to each side of the equation. -5 + 5 + -1d = 0 + 5 Combine like terms: -5 + 5 = 0 0 + -1d = 0 + 5 -1d = 0 + 5 Combine like terms: 0 + 5 = 5 -1d = 5 Divide each side by '-1'. d = -5 Simplifying d = -5

Subproblem 2

Set the factor '(1 + -1d)' equal to zero and attempt to solve: Simplifying 1 + -1d = 0 Solving 1 + -1d = 0 Move all terms containing d to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -1d = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -1d = 0 + -1 -1d = 0 + -1 Combine like terms: 0 + -1 = -1 -1d = -1 Divide each side by '-1'. d = 1 Simplifying d = 1

Solution

d = {-5, 1}

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