(d-11)(d-11)=0

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Solution for (d-11)(d-11)=0 equation: 



(d-11)(d-11)=0

We multiply parentheses ..

(+d^2-11d-11d+121)=0

We get rid of parentheses

d^2-11d-11d+121=0

We add all the numbers together, and all the variables

d^2-22d+121=0

a = 1; b = -22; c = +121;
Δ = b2-4ac
Δ = -222-4·1·121
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$d=\frac{-b}{2a}=\frac{22}{2}=11$

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