(d-2)/3=(d+2)/7

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Solution for (d-2)/3=(d+2)/7 equation: 



(d-2)/3=(d+2)/7

We move all terms to the left:

(d-2)/3-((d+2)/7)=0

We calculate fractions


d/()+(-((d+2)*3)/()=0



We calculate terms in parentheses: +(-((d+2)*3)/(), so:

-((d+2)*3)/(

We multiply all the terms by the denominator


-((d+2)*3)



We calculate terms in parentheses: -((d+2)*3), so:

(d+2)*3

We multiply parentheses

3d+6

Back to the equation:

-(3d+6)



We get rid of parentheses

-3d-6

Back to the equation:

+(-3d-6)



We get rid of parentheses

d/()-3d-6=0

We multiply all the terms by the denominator


d-3d*()-6*()=0

We add all the numbers together, and all the variables

d-3d*()=0

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