(d/4)-(3/d)=(5d+7/20)

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Solution for (d/4)-(3/d)=(5d+7/20) equation: 


D( d )

d = 0

d = 0

d = 0

d in (-oo:0) U (0:+oo)

d/4-(3/d) = 5*d+7/20 // - 5*d+7/20

d/4-(5*d)-(3/d)-(7/20) = 0

d/4-5*d-3*d^-1-7/20 = 0

-19/4*d^1-3*d^-1-7/20*d^0 = 0

(-19/4*d^2-7/20*d^1-3*d^0)/(d^1) = 0 // * d^2

d^1*(-19/4*d^2-7/20*d^1-3*d^0) = 0

d^1

(-19/4)*d^2+(-7/20)*d-3 = 0

(-19/4)*d^2+(-7/20)*d-3 = 0

DELTA = (-7/20)^2-(-3*4*(-19/4))

DELTA = -22751/400

DELTA < 0

d in { } 

d belongs to the empty set

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