(d2+3)=(d2+2d+1)

Solution for (d2+3)=(d2+2d+1) equation:

(d2+3)=(d2+2d+1)

We move all terms to the left:

(d2+3)-((d2+2d+1))=0

We add all the numbers together, and all the variables

(+d^2+3)-((+d^2+2d+1))=0

We get rid of parentheses

d^2-((+d^2+2d+1))+3=0


We calculate terms in parentheses: -((+d^2+2d+1)), so:

(+d^2+2d+1)

We get rid of parentheses

d^2+2d+1

Back to the equation:

-(d^2+2d+1)


We get rid of parentheses

d^2-d^2-2d-1+3=0

We add all the numbers together, and all the variables

-2d+2=0

We move all terms containing d to the left, all other terms to the right

-2d=-2

d=-2/-2

d=1