(e+1)/9=(e+2)/8

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Solution for (e+1)/9=(e+2)/8 equation: 



(e+1)/9=(e+2)/8

We move all terms to the left:

(e+1)/9-((e+2)/8)=0

We calculate fractions


e/()+(-((e+2)*9)/()=0



We calculate terms in parentheses: +(-((e+2)*9)/(), so:

-((e+2)*9)/(

We multiply all the terms by the denominator


-((e+2)*9)



We calculate terms in parentheses: -((e+2)*9), so:

(e+2)*9

We multiply parentheses

9e+18

Back to the equation:

-(9e+18)



We get rid of parentheses

-9e-18

Back to the equation:

+(-9e-18)



We get rid of parentheses

e/()-9e-18=0

We multiply all the terms by the denominator


e-9e*()-18*()=0

We add all the numbers together, and all the variables

e-9e*()=0

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