(f+1)-2=2(3+f)

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Solution for (f+1)-2=2(3+f) equation:



(f+1)-2=2(3+f)
We move all terms to the left:
(f+1)-2-(2(3+f))=0
We add all the numbers together, and all the variables
(f+1)-(2(f+3))-2=0
We get rid of parentheses
f-(2(f+3))+1-2=0
We calculate terms in parentheses: -(2(f+3)), so:
2(f+3)
We multiply parentheses
2f+6
Back to the equation:
-(2f+6)
We add all the numbers together, and all the variables
f-(2f+6)-1=0
We get rid of parentheses
f-2f-6-1=0
We add all the numbers together, and all the variables
-1f-7=0
We move all terms containing f to the left, all other terms to the right
-f=7
f=7/-1
f=-7

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