(f+1)-2=2(3+f)

Solution for (f+1)-2=2(3+f) equation:

(f+1)-2=2(3+f)

We move all terms to the left:

(f+1)-2-(2(3+f))=0

We add all the numbers together, and all the variables

(f+1)-(2(f+3))-2=0

We get rid of parentheses

f-(2(f+3))+1-2=0


We calculate terms in parentheses: -(2(f+3)), so:

2(f+3)

We multiply parentheses

2f+6

Back to the equation:

-(2f+6)


We add all the numbers together, and all the variables

f-(2f+6)-1=0

We get rid of parentheses

f-2f-6-1=0

We add all the numbers together, and all the variables

-1f-7=0

We move all terms containing f to the left, all other terms to the right

-f=7

f=7/-1

f=-7