(f+2)=(2f-5)

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Solution for (f+2)=(2f-5) equation: 



(f+2)=(2f-5)

We move all terms to the left:

(f+2)-((2f-5))=0

We get rid of parentheses

f-((2f-5))+2=0



We calculate terms in parentheses: -((2f-5)), so:

(2f-5)

We get rid of parentheses

2f-5

Back to the equation:

-(2f-5)



We get rid of parentheses

f-2f+5+2=0

We add all the numbers together, and all the variables

-1f+7=0

We move all terms containing f to the left, all other terms to the right

-f=-7

f=-7/-1

f=+7

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