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(f+6)(f+6)=144
We move all terms to the left:
(f+6)(f+6)-(144)=0
We multiply parentheses ..
(+f^2+6f+6f+36)-144=0
We get rid of parentheses
f^2+6f+6f+36-144=0
We add all the numbers together, and all the variables
f^2+12f-108=0
a = 1; b = 12; c = -108;
Δ = b2-4ac
Δ = 122-4·1·(-108)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-24}{2*1}=\frac{-36}{2} =-18 $$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+24}{2*1}=\frac{12}{2} =6 $
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