(f-3)(f+2)=f(f-1)

Solution for (f-3)(f+2)=f(f-1) equation:

Simplifying
(f + -3)(f + 2) = f(f + -1)

Reorder the terms:
(-3 + f)(f + 2) = f(f + -1)

Reorder the terms:
(-3 + f)(2 + f) = f(f + -1)

Multiply (-3 + f) * (2 + f)
(-3(2 + f) + f(2 + f)) = f(f + -1)
((2 * -3 + f * -3) + f(2 + f)) = f(f + -1)
((-6 + -3f) + f(2 + f)) = f(f + -1)
(-6 + -3f + (2 * f + f * f)) = f(f + -1)
(-6 + -3f + (2f + f2)) = f(f + -1)

Combine like terms: -3f + 2f = -1f
(-6 + -1f + f2) = f(f + -1)

Reorder the terms:
-6 + -1f + f2 = f(-1 + f)
-6 + -1f + f2 = (-1 * f + f * f)
-6 + -1f + f2 = (-1f + f2)

Add 'f' to each side of the equation.
-6 + -1f + f + f2 = -1f + f + f2

Combine like terms: -1f + f = 0
-6 + 0 + f2 = -1f + f + f2
-6 + f2 = -1f + f + f2

Combine like terms: -1f + f = 0
-6 + f2 = 0 + f2
-6 + f2 = f2

Add '-1f2' to each side of the equation.
-6 + f2 + -1f2 = f2 + -1f2

Combine like terms: f2 + -1f2 = 0
-6 + 0 = f2 + -1f2
-6 = f2 + -1f2

Combine like terms: f2 + -1f2 = 0
-6 = 0

Solving
-6 = 0

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.