(f=3)(f-5)=0

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Solution for (f=3)(f-5)=0 equation: 



(f=3)(f-5)=0

We move all terms to the left:

(f-(3)(f-5))=0



We calculate terms in parentheses: +(f-3(f-5)), so:

f-3(f-5)

We multiply parentheses

f-3f+15

We add all the numbers together, and all the variables

-2f+15

Back to the equation:

+(-2f+15)



We get rid of parentheses

-2f+15=0

We move all terms containing f to the left, all other terms to the right

-2f=-15

f=-15/-2

f=7+1/2

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