(g+1)-(2g+4)=3(g-2)+8

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Solution for (g+1)-(2g+4)=3(g-2)+8 equation: 



(g+1)-(2g+4)=3(g-2)+8

We move all terms to the left:

(g+1)-(2g+4)-(3(g-2)+8)=0

We get rid of parentheses

g-2g-(3(g-2)+8)+1-4=0



We calculate terms in parentheses: -(3(g-2)+8), so:

3(g-2)+8

We multiply parentheses

3g-6+8

We add all the numbers together, and all the variables

3g+2

Back to the equation:

-(3g+2)



We add all the numbers together, and all the variables

-1g-(3g+2)-3=0

We get rid of parentheses

-1g-3g-2-3=0

We add all the numbers together, and all the variables

-4g-5=0

We move all terms containing g to the left, all other terms to the right

-4g=5

g=5/-4

g=-1+1/4

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