(g-23)+(g-28)=g

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Solution for (g-23)+(g-28)=g equation: 



(g-23)+(g-28)=g

We move all terms to the left:

(g-23)+(g-28)-(g)=0

We add all the numbers together, and all the variables

-1g+(g-23)+(g-28)=0

We get rid of parentheses

-1g+g+g-23-28=0

We add all the numbers together, and all the variables

g-51=0

We move all terms containing g to the left, all other terms to the right

g=51

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