(g-4)(8g+4)=0

Solution for (g-4)(8g+4)=0 equation:

(g-4)(8g+4)=0

We multiply parentheses ..

(+8g^2+4g-32g-16)=0

We get rid of parentheses

8g^2+4g-32g-16=0

We add all the numbers together, and all the variables

8g^2-28g-16=0

a = 8; b = -28; c = -16;
Δ = b2-4ac
Δ = -282-4·8·(-16)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-36}{2*8}=\frac{-8}{16}
=-1/2
$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+36}{2*8}=\frac{64}{16}
=4
$