(h)(h+4)(6)=126

Solution for (h)(h+4)(6)=126 equation:

(h)(h+4)(6)=126

We move all terms to the left:

(h)(h+4)(6)-(126)=0

We multiply parentheses

6h^2+24h-126=0

a = 6; b = 24; c = -126;
Δ = b2-4ac
Δ = 242-4·6·(-126)
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-60}{2*6}=\frac{-84}{12}
=-7
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+60}{2*6}=\frac{36}{12}
=3
$