(h+7)(2h+1)=0

Solution for (h+7)(2h+1)=0 equation:

Simplifying
(h + 7)(2h + 1) = 0

Reorder the terms:
(7 + h)(2h + 1) = 0

Reorder the terms:
(7 + h)(1 + 2h) = 0

Multiply (7 + h) * (1 + 2h)
(7(1 + 2h) + h(1 + 2h)) = 0
((1 * 7 + 2h * 7) + h(1 + 2h)) = 0
((7 + 14h) + h(1 + 2h)) = 0
(7 + 14h + (1 * h + 2h * h)) = 0
(7 + 14h + (1h + 2h2)) = 0

Combine like terms: 14h + 1h = 15h
(7 + 15h + 2h2) = 0

Solving
7 + 15h + 2h2 = 0

Solving for variable 'h'.

Factor a trinomial.
(7 + h)(1 + 2h) = 0

Subproblem 1
Set the factor '(7 + h)' equal to zero and attempt to solve:

Simplifying
7 + h = 0

Solving
7 + h = 0

Move all terms containing h to the left, all other terms to the right.

Add '-7' to each side of the equation.
7 + -7 + h = 0 + -7

Combine like terms: 7 + -7 = 0
0 + h = 0 + -7
h = 0 + -7

Combine like terms: 0 + -7 = -7
h = -7

Simplifying
h = -7
Subproblem 2
Set the factor '(1 + 2h)' equal to zero and attempt to solve:

Simplifying
1 + 2h = 0

Solving
1 + 2h = 0

Move all terms containing h to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 2h = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 2h = 0 + -1
2h = 0 + -1

Combine like terms: 0 + -1 = -1
2h = -1

Divide each side by '2'.
h = -0.5

Simplifying
h = -0.5
Solution
h = {-7, -0.5}