(h+8)(2h-9)=0

Solution for (h+8)(2h-9)=0 equation:

(h+8)(2h-9)=0

We multiply parentheses ..

(+2h^2-9h+16h-72)=0

We get rid of parentheses

2h^2-9h+16h-72=0

We add all the numbers together, and all the variables

2h^2+7h-72=0

a = 2; b = 7; c = -72;
Δ = b2-4ac
Δ = 72-4·2·(-72)
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-25}{2*2}=\frac{-32}{4}
=-8
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+25}{2*2}=\frac{18}{4}
=4+1/2
$