(h+8)(4h-3)=0

Solution for (h+8)(4h-3)=0 equation:

(h+8)(4h-3)=0

We multiply parentheses ..

(+4h^2-3h+32h-24)=0

We get rid of parentheses

4h^2-3h+32h-24=0

We add all the numbers together, and all the variables

4h^2+29h-24=0

a = 4; b = 29; c = -24;
Δ = b2-4ac
Δ = 292-4·4·(-24)
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-35}{2*4}=\frac{-64}{8}
=-8
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+35}{2*4}=\frac{6}{8}
=3/4
$