(h-1)+4(3+h)=56

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Solution for (h-1)+4(3+h)=56 equation: 



(h-1)+4(3+h)=56

We move all terms to the left:

(h-1)+4(3+h)-(56)=0

We add all the numbers together, and all the variables

(h-1)+4(h+3)-56=0

We multiply parentheses

(h-1)+4h+12-56=0

We get rid of parentheses

h+4h-1+12-56=0

We add all the numbers together, and all the variables

5h-45=0

We move all terms containing h to the left, all other terms to the right

5h=45

h=45/5

h=9

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