(h-4)(h+2)=0

Solution for (h-4)(h+2)=0 equation:

Simplifying
(h + -4)(h + 2) = 0

Reorder the terms:
(-4 + h)(h + 2) = 0

Reorder the terms:
(-4 + h)(2 + h) = 0

Multiply (-4 + h) * (2 + h)
(-4(2 + h) + h(2 + h)) = 0
((2 * -4 + h * -4) + h(2 + h)) = 0
((-8 + -4h) + h(2 + h)) = 0
(-8 + -4h + (2 * h + h * h)) = 0
(-8 + -4h + (2h + h2)) = 0

Combine like terms: -4h + 2h = -2h
(-8 + -2h + h2) = 0

Solving
-8 + -2h + h2 = 0

Solving for variable 'h'.

Factor a trinomial.
(-2 + -1h)(4 + -1h) = 0

Subproblem 1
Set the factor '(-2 + -1h)' equal to zero and attempt to solve:

Simplifying
-2 + -1h = 0

Solving
-2 + -1h = 0

Move all terms containing h to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + -1h = 0 + 2

Combine like terms: -2 + 2 = 0
0 + -1h = 0 + 2
-1h = 0 + 2

Combine like terms: 0 + 2 = 2
-1h = 2

Divide each side by '-1'.
h = -2

Simplifying
h = -2
Subproblem 2
Set the factor '(4 + -1h)' equal to zero and attempt to solve:

Simplifying
4 + -1h = 0

Solving
4 + -1h = 0

Move all terms containing h to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + -1h = 0 + -4

Combine like terms: 4 + -4 = 0
0 + -1h = 0 + -4
-1h = 0 + -4

Combine like terms: 0 + -4 = -4
-1h = -4

Divide each side by '-1'.
h = 4

Simplifying
h = 4
Solution
h = {-2, 4}