(h-4)+(2+h)=(h+6)-(h+2)

Solution for (h-4)+(2+h)=(h+6)-(h+2) equation:

Simplifying
(h + -4) + (2 + h) = (h + 6) + -1(h + 2)

Reorder the terms:
(-4 + h) + (2 + h) = (h + 6) + -1(h + 2)

Remove parenthesis around (-4 + h)
-4 + h + (2 + h) = (h + 6) + -1(h + 2)

Remove parenthesis around (2 + h)
-4 + h + 2 + h = (h + 6) + -1(h + 2)

Reorder the terms:
-4 + 2 + h + h = (h + 6) + -1(h + 2)

Combine like terms: -4 + 2 = -2
-2 + h + h = (h + 6) + -1(h + 2)

Combine like terms: h + h = 2h
-2 + 2h = (h + 6) + -1(h + 2)

Reorder the terms:
-2 + 2h = (6 + h) + -1(h + 2)

Remove parenthesis around (6 + h)
-2 + 2h = 6 + h + -1(h + 2)

Reorder the terms:
-2 + 2h = 6 + h + -1(2 + h)
-2 + 2h = 6 + h + (2 * -1 + h * -1)
-2 + 2h = 6 + h + (-2 + -1h)

Reorder the terms:
-2 + 2h = 6 + -2 + h + -1h

Combine like terms: 6 + -2 = 4
-2 + 2h = 4 + h + -1h

Combine like terms: h + -1h = 0
-2 + 2h = 4 + 0
-2 + 2h = 4

Solving
-2 + 2h = 4

Solving for variable 'h'.

Move all terms containing h to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + 2h = 4 + 2

Combine like terms: -2 + 2 = 0
0 + 2h = 4 + 2
2h = 4 + 2

Combine like terms: 4 + 2 = 6
2h = 6

Divide each side by '2'.
h = 3

Simplifying
h = 3