(h-7)(2h+1)=0

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Solution for (h-7)(2h+1)=0 equation:


Simplifying
(h + -7)(2h + 1) = 0

Reorder the terms:
(-7 + h)(2h + 1) = 0

Reorder the terms:
(-7 + h)(1 + 2h) = 0

Multiply (-7 + h) * (1 + 2h)
(-7(1 + 2h) + h(1 + 2h)) = 0
((1 * -7 + 2h * -7) + h(1 + 2h)) = 0
((-7 + -14h) + h(1 + 2h)) = 0
(-7 + -14h + (1 * h + 2h * h)) = 0
(-7 + -14h + (1h + 2h2)) = 0

Combine like terms: -14h + 1h = -13h
(-7 + -13h + 2h2) = 0

Solving
-7 + -13h + 2h2 = 0

Solving for variable 'h'.

Factor a trinomial.
(-1 + -2h)(7 + -1h) = 0

Subproblem 1

Set the factor '(-1 + -2h)' equal to zero and attempt to solve: Simplifying -1 + -2h = 0 Solving -1 + -2h = 0 Move all terms containing h to the left, all other terms to the right. Add '1' to each side of the equation. -1 + 1 + -2h = 0 + 1 Combine like terms: -1 + 1 = 0 0 + -2h = 0 + 1 -2h = 0 + 1 Combine like terms: 0 + 1 = 1 -2h = 1 Divide each side by '-2'. h = -0.5 Simplifying h = -0.5

Subproblem 2

Set the factor '(7 + -1h)' equal to zero and attempt to solve: Simplifying 7 + -1h = 0 Solving 7 + -1h = 0 Move all terms containing h to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + -1h = 0 + -7 Combine like terms: 7 + -7 = 0 0 + -1h = 0 + -7 -1h = 0 + -7 Combine like terms: 0 + -7 = -7 -1h = -7 Divide each side by '-1'. h = 7 Simplifying h = 7

Solution

h = {-0.5, 7}

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