(i)(5i)(-1+i)=

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Solution for (i)(5i)(-1+i)= equation:


Simplifying
(i)(5i)(-1 + i) = 0

Remove parenthesis around (5i)
i * 5i(-1 + i) = 0

Reorder the terms for easier multiplication:
5i * i(-1 + i) = 0

Multiply i * i
5i2(-1 + i) = 0
(-1 * 5i2 + i * 5i2) = 0
(-5i2 + 5i3) = 0

Solving
-5i2 + 5i3 = 0

Solving for variable 'i'.

Factor out the Greatest Common Factor (GCF), '5i2'.
5i2(-1 + i) = 0

Ignore the factor 5.

Subproblem 1

Set the factor 'i2' equal to zero and attempt to solve: Simplifying i2 = 0 Solving i2 = 0 Move all terms containing i to the left, all other terms to the right. Simplifying i2 = 0 Take the square root of each side: i = {0}

Subproblem 2

Set the factor '(-1 + i)' equal to zero and attempt to solve: Simplifying -1 + i = 0 Solving -1 + i = 0 Move all terms containing i to the left, all other terms to the right. Add '1' to each side of the equation. -1 + 1 + i = 0 + 1 Combine like terms: -1 + 1 = 0 0 + i = 0 + 1 i = 0 + 1 Combine like terms: 0 + 1 = 1 i = 1 Simplifying i = 1

Solution

i = {0, 1}

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