(i-1)-(i+2)-(i+3)=i-2i

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Solution for (i-1)-(i+2)-(i+3)=i-2i equation:


Simplifying
(i + -1) + -1(i + 2) + -1(i + 3) = i + -2i

Reorder the terms:
(-1 + i) + -1(i + 2) + -1(i + 3) = i + -2i

Remove parenthesis around (-1 + i)
-1 + i + -1(i + 2) + -1(i + 3) = i + -2i

Reorder the terms:
-1 + i + -1(2 + i) + -1(i + 3) = i + -2i
-1 + i + (2 * -1 + i * -1) + -1(i + 3) = i + -2i
-1 + i + (-2 + -1i) + -1(i + 3) = i + -2i

Reorder the terms:
-1 + i + -2 + -1i + -1(3 + i) = i + -2i
-1 + i + -2 + -1i + (3 * -1 + i * -1) = i + -2i
-1 + i + -2 + -1i + (-3 + -1i) = i + -2i

Reorder the terms:
-1 + -2 + -3 + i + -1i + -1i = i + -2i

Combine like terms: -1 + -2 = -3
-3 + -3 + i + -1i + -1i = i + -2i

Combine like terms: -3 + -3 = -6
-6 + i + -1i + -1i = i + -2i

Combine like terms: i + -1i = 0
-6 + 0 + -1i = i + -2i
-6 + -1i = i + -2i

Combine like terms: i + -2i = -1i
-6 + -1i = -1i

Add 'i' to each side of the equation.
-6 + -1i + i = -1i + i

Combine like terms: -1i + i = 0
-6 + 0 = -1i + i
-6 = -1i + i

Combine like terms: -1i + i = 0
-6 = 0

Solving
-6 = 0

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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