(iZ+2)(3Z-1+i)=0

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Solution for (iZ+2)(3Z-1+i)=0 equation:


Simplifying
(iZ + 2)(3Z + -1 + i) = 0

Reorder the terms:
(2 + iZ)(3Z + -1 + i) = 0

Reorder the terms:
(2 + iZ)(-1 + 3Z + i) = 0

Multiply (2 + iZ) * (-1 + 3Z + i)
(2(-1 + 3Z + i) + iZ(-1 + 3Z + i)) = 0
((-1 * 2 + 3Z * 2 + i * 2) + iZ(-1 + 3Z + i)) = 0
((-2 + 6Z + 2i) + iZ(-1 + 3Z + i)) = 0
(-2 + 6Z + 2i + (-1 * iZ + 3Z * iZ + i * iZ)) = 0
(-2 + 6Z + 2i + (-1iZ + 3iZ2 + i2Z)) = 0
(-2 + 6Z + 2i + -1iZ + 3iZ2 + i2Z) = 0

Solving
-2 + 6Z + 2i + -1iZ + 3iZ2 + i2Z = 0

Solving for variable 'Z'.

The solution to this equation could not be determined.

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