(iz+2)(2z+3-i)=0

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Solution for (iz+2)(2z+3-i)=0 equation:


Simplifying
(iz + 2)(2z + 3 + -1i) = 0

Reorder the terms:
(2 + iz)(2z + 3 + -1i) = 0

Reorder the terms:
(2 + iz)(3 + -1i + 2z) = 0

Multiply (2 + iz) * (3 + -1i + 2z)
(2(3 + -1i + 2z) + iz(3 + -1i + 2z)) = 0
((3 * 2 + -1i * 2 + 2z * 2) + iz(3 + -1i + 2z)) = 0
((6 + -2i + 4z) + iz(3 + -1i + 2z)) = 0
(6 + -2i + 4z + (3 * iz + -1i * iz + 2z * iz)) = 0

Reorder the terms:
(6 + -2i + 4z + (3iz + 2iz2 + -1i2z)) = 0
(6 + -2i + 4z + (3iz + 2iz2 + -1i2z)) = 0

Reorder the terms:
(6 + -2i + 3iz + 2iz2 + -1i2z + 4z) = 0
(6 + -2i + 3iz + 2iz2 + -1i2z + 4z) = 0

Solving
6 + -2i + 3iz + 2iz2 + -1i2z + 4z = 0

Solving for variable 'i'.

The solution to this equation could not be determined.

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