(j)+(14j+2)+(2j-1)=35

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Solution for (j)+(14j+2)+(2j-1)=35 equation:


Simplifying
(j) + (14j + 2) + (2j + -1) = 35
j + (14j + 2) + (2j + -1) = 35

Reorder the terms:
j + (2 + 14j) + (2j + -1) = 35

Remove parenthesis around (2 + 14j)
j + 2 + 14j + (2j + -1) = 35

Reorder the terms:
j + 2 + 14j + (-1 + 2j) = 35

Remove parenthesis around (-1 + 2j)
j + 2 + 14j + -1 + 2j = 35

Reorder the terms:
2 + -1 + j + 14j + 2j = 35

Combine like terms: 2 + -1 = 1
1 + j + 14j + 2j = 35

Combine like terms: j + 14j = 15j
1 + 15j + 2j = 35

Combine like terms: 15j + 2j = 17j
1 + 17j = 35

Solving
1 + 17j = 35

Solving for variable 'j'.

Move all terms containing j to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 17j = 35 + -1

Combine like terms: 1 + -1 = 0
0 + 17j = 35 + -1
17j = 35 + -1

Combine like terms: 35 + -1 = 34
17j = 34

Divide each side by '17'.
j = 2

Simplifying
j = 2

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