(k+(4k/3))=20

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Solution for (k+(4k/3))=20 equation: 



(k+(4k/3))=20

We move all terms to the left:

(k+(4k/3))-(20)=0

We add all the numbers together, and all the variables

(k+(+4k/3))-20=0

We multiply all the terms by the denominator


(k+(+4k-20*3))=0



We calculate terms in parentheses: +(k+(+4k-20*3)), so:

k+(+4k-20*3)

We add all the numbers together, and all the variables

k+(4k-60)

We get rid of parentheses

k+4k-60

We add all the numbers together, and all the variables

5k-60

Back to the equation:

+(5k-60)



We get rid of parentheses

5k-60=0

We move all terms containing k to the left, all other terms to the right

5k=60

k=60/5

k=12

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