(k+1)/(-2k+3)=k+1

Solution for (k+1)/(-2k+3)=k+1 equation:

(k+1)/(-2k+3)=k+1

We move all terms to the left:

(k+1)/(-2k+3)-(k+1)=0


Domain of the equation: (-2k+3)!=0

We move all terms containing k to the left, all other terms to the right

-2k!=-3

k!=-3/-2

k!=1+1/2

k∈R


We get rid of parentheses

(k+1)/(-2k+3)-k-1=0

We multiply all the terms by the denominator


(k+1)-k*(-2k+3)-1*(-2k+3)=0

We multiply parentheses

2k^2+(k+1)-3k-1*(-2k+3)=0

We get rid of parentheses

2k^2+k-3k-1*(-2k+3)+1=0

We add all the numbers together, and all the variables

2k^2-2k-1*(-2k+3)+1=0

We move all terms containing k to the left, all other terms to the right

2k^2-2k-1*(-2k+3)=-1