(k+1)2-4(k+4)1=0

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Solution for (k+1)2-4(k+4)1=0 equation: 



(k+1)2-4(k+4)1=0

We multiply parentheses

2k-4k+2-16=0

We add all the numbers together, and all the variables

-2k-14=0

We move all terms containing k to the left, all other terms to the right

-2k=14

k=14/-2

k=-7

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