(k+1)x(k+1)+4(k-2)+2k=0

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Solution for (k+1)x(k+1)+4(k-2)+2k=0 equation:


Simplifying
(k + 1) * x(k + 1) + 4(k + -2) + 2k = 0

Reorder the terms:
(1 + k) * x(k + 1) + 4(k + -2) + 2k = 0

Reorder the terms:
(1 + k) * x(1 + k) + 4(k + -2) + 2k = 0

Reorder the terms for easier multiplication:
x(1 + k)(1 + k) + 4(k + -2) + 2k = 0

Multiply (1 + k) * (1 + k)
x(1(1 + k) + k(1 + k)) + 4(k + -2) + 2k = 0
x((1 * 1 + k * 1) + k(1 + k)) + 4(k + -2) + 2k = 0
x((1 + 1k) + k(1 + k)) + 4(k + -2) + 2k = 0
x(1 + 1k + (1 * k + k * k)) + 4(k + -2) + 2k = 0
x(1 + 1k + (1k + k2)) + 4(k + -2) + 2k = 0

Combine like terms: 1k + 1k = 2k
x(1 + 2k + k2) + 4(k + -2) + 2k = 0
(1 * x + 2k * x + k2 * x) + 4(k + -2) + 2k = 0

Reorder the terms:
(2kx + k2x + 1x) + 4(k + -2) + 2k = 0
(2kx + k2x + 1x) + 4(k + -2) + 2k = 0

Reorder the terms:
2kx + k2x + 1x + 4(-2 + k) + 2k = 0
2kx + k2x + 1x + (-2 * 4 + k * 4) + 2k = 0
2kx + k2x + 1x + (-8 + 4k) + 2k = 0

Reorder the terms:
-8 + 4k + 2k + 2kx + k2x + 1x = 0

Combine like terms: 4k + 2k = 6k
-8 + 6k + 2kx + k2x + 1x = 0

Solving
-8 + 6k + 2kx + k2x + 1x = 0

Solving for variable 'k'.

The solution to this equation could not be determined.

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