(k+2)/(3)=(k-4)/(5)

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Solution for (k+2)/(3)=(k-4)/(5) equation: 


k in (-oo:+oo)

(k+2)/3 = (k-4)/5 // - (k-4)/5

(k+2)/3-((k-4)/5) = 0

(k+2)/3+(-1*(k-4))/5 = 0

(5*(k+2))/(3*5)+(-1*3*(k-4))/(3*5) = 0

5*(k+2)-1*3*(k-4) = 0

2*k+22 = 0

(2*k+22)/(3*5) = 0

(2*k+22)/(3*5) = 0 // * 3*5

2*k+22 = 0

2*k+22 = 0 // - 22

2*k = -22 // : 2

k = -22/2

k = -11

k = -11

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