(k+4)/2=(k+9)/3

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Solution for (k+4)/2=(k+9)/3 equation: 



(k+4)/2=(k+9)/3

We move all terms to the left:

(k+4)/2-((k+9)/3)=0

We calculate fractions


k/()+(-((k+9)*2)/()=0



We calculate terms in parentheses: +(-((k+9)*2)/(), so:

-((k+9)*2)/(

We multiply all the terms by the denominator


-((k+9)*2)



We calculate terms in parentheses: -((k+9)*2), so:

(k+9)*2

We multiply parentheses

2k+18

Back to the equation:

-(2k+18)



We get rid of parentheses

-2k-18

Back to the equation:

+(-2k-18)



We get rid of parentheses

k/()-2k-18=0

We multiply all the terms by the denominator


k-2k*()-18*()=0

We add all the numbers together, and all the variables

k-2k*()=0

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