(k-1)+(6-2k)=2

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Solution for (k-1)+(6-2k)=2 equation:



(k-1)+(6-2k)=2
We move all terms to the left:
(k-1)+(6-2k)-(2)=0
We add all the numbers together, and all the variables
(k-1)+(-2k+6)-2=0
We get rid of parentheses
k-2k-1+6-2=0
We add all the numbers together, and all the variables
-1k+3=0
We move all terms containing k to the left, all other terms to the right
-k=-3
k=-3/-1
k=+3

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