(k-3)(k+2)k=1

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Solution for (k-3)(k+2)k=1 equation: 


Simplifying
(k + -3)(k + 2) * k = 1

Reorder the terms:
(-3 + k)(k + 2) * k = 1

Reorder the terms:
(-3 + k)(2 + k) * k = 1

Reorder the terms for easier multiplication:
k(-3 + k)(2 + k) = 1

Multiply (-3 + k) * (2 + k)
k(-3(2 + k) + k(2 + k)) = 1
k((2 * -3 + k * -3) + k(2 + k)) = 1
k((-6 + -3k) + k(2 + k)) = 1
k(-6 + -3k + (2 * k + k * k)) = 1
k(-6 + -3k + (2k + k2)) = 1

Combine like terms: -3k + 2k = -1k
k(-6 + -1k + k2) = 1
(-6 * k + -1k * k + k2 * k) = 1
(-6k + -1k2 + k3) = 1

Solving
-6k + -1k2 + k3 = 1

Solving for variable 'k'.

Reorder the terms:
-1 + -6k + -1k2 + k3 = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + -6k + -1k2 + k3 = 0

The solution to this equation could not be determined.

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