(k-3)/(1-2k)=2

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Solution for (k-3)/(1-2k)=2 equation: 



(k-3)/(1-2k)=2

We move all terms to the left:

(k-3)/(1-2k)-(2)=0



Domain of the equation: (1-2k)!=0

We move all terms containing k to the left, all other terms to the right

-2k!=-1

k!=-1/-2

k!=1/2

k∈R



We add all the numbers together, and all the variables

(k-3)/(-2k+1)-2=0

We multiply all the terms by the denominator


(k-3)-2*(-2k+1)=0

We multiply parentheses

(k-3)+4k-2=0

We get rid of parentheses

k+4k-3-2=0

We add all the numbers together, and all the variables

5k-5=0

We move all terms containing k to the left, all other terms to the right

5k=5

k=5/5

k=1

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