(k=4)(3k+2)=

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Solution for (k=4)(3k+2)= equation: 



(k=4)(3k+2)=

We move all terms to the left:

(k-(4)(3k+2))=0



We calculate terms in parentheses: +(k-4(3k+2)), so:

k-4(3k+2)

We multiply parentheses

k-12k-8

We add all the numbers together, and all the variables

-11k-8

Back to the equation:

+(-11k-8)



We get rid of parentheses

-11k-8=0

We move all terms containing k to the left, all other terms to the right

-11k=8

k=8/-11

k=-8/11

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