(ln(0.8/(0.8-x)))=1

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Solution for (ln(0.8/(0.8-x)))=1 equation: 


D( x )

0.8/(0.8-x) <= 0

0.8-x = 0

0.8/(0.8-x) <= 0

0.8/(0.8-x) <= 0

( 0.8-x )

0.8-x <= 0

-x <= -0.8 // * -1

x >= 0.8

( 0.8 )

0.8 <= 0

x belongs to the empty set

	(-oo:0.8)	(0.8:+oo)
0.8-x	+	-
0.8	+	+


0.8-x = 0

0.8-x = 0

0.8-x = 0 // - 0.8

-x = -0.8 // * -1

x = 0.8

x in (-oo:0.8)

ln(0.8/(0.8-x)) = 1 // - 1

ln(0.8/(0.8-x))-1 = 0

ln(0.8/(0.8-x))-1 = 0 // + 1

ln(0.8/(0.8-x)) = 1

ln(0.8/(0.8-x)) = ln(e^1)

0.8/(0.8-x) = e^1

0.8/(0.8-x)-e^1 = 0

0.8/(0.8-x)-e = 0

0.8/(0.8-x)+(-e*(0.8-x))/(0.8-x) = 0

0.8-e*(0.8-x) = 0

e*x-0.8*e+0.8 = 0

(e*x-0.8*e+0.8)/(0.8-x) = 0

(e*x-0.8*e+0.8)/(0.8-x) = 0 // * 0.8-x

e*x-0.8*e+0.8 = 0

e*x-0.8*e+0.8 = 0 // - 0.8-0.8*e

e*x = -(0.8-0.8*e) // : e

x = (-(0.8-0.8*e))/e

x = -(e^-1*(0.8-0.8*e))

x = -(e^-1*(0.8-0.8*e))

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