(ln(2x+1)*ln(2x-1))=1

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Solution for (ln(2x+1)*ln(2x-1))=1 equation: 


Simplifying
(ln(2x + 1) * ln(2x + -1)) = 1

Reorder the terms:
(ln(1 + 2x) * ln(2x + -1)) = 1

Reorder the terms:
(ln(1 + 2x) * ln(-1 + 2x)) = 1

Reorder the terms for easier multiplication:
(ln * ln(1 + 2x)(-1 + 2x)) = 1

Multiply ln * ln
(l2n2(1 + 2x)(-1 + 2x)) = 1

Multiply (1 + 2x) * (-1 + 2x)
(l2n2(1(-1 + 2x) + 2x * (-1 + 2x))) = 1
(l2n2((-1 * 1 + 2x * 1) + 2x * (-1 + 2x))) = 1
(l2n2((-1 + 2x) + 2x * (-1 + 2x))) = 1
(l2n2(-1 + 2x + (-1 * 2x + 2x * 2x))) = 1
(l2n2(-1 + 2x + (-2x + 4x2))) = 1

Combine like terms: 2x + -2x = 0
(l2n2(-1 + 0 + 4x2)) = 1
(l2n2(-1 + 4x2)) = 1
((-1 * l2n2 + 4x2 * l2n2)) = 1
((-1l2n2 + 4l2n2x2)) = 1
(-1l2n2 + 4l2n2x2) = 1

Remove parenthesis around (-1l2n2 + 4l2n2x2)
-1l2n2 + 4l2n2x2 = 1

Solving
-1l2n2 + 4l2n2x2 = 1

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Reorder the terms:
-1 + -1l2n2 + 4l2n2x2 = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + -1l2n2 + 4l2n2x2 = 0

The solution to this equation could not be determined.

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