(lnx+1)(lnx-1)=0

Solution for (lnx+1)(lnx-1)=0 equation:

Simplifying
(lnx + 1)(lnx + -1) = 0

Reorder the terms:
(1 + lnx)(lnx + -1) = 0

Reorder the terms:
(1 + lnx)(-1 + lnx) = 0

Multiply (1 + lnx) * (-1 + lnx)
(1(-1 + lnx) + lnx(-1 + lnx)) = 0
((-1 * 1 + lnx * 1) + lnx(-1 + lnx)) = 0
((-1 + 1lnx) + lnx(-1 + lnx)) = 0
(-1 + 1lnx + (-1 * lnx + lnx * lnx)) = 0
(-1 + 1lnx + (-1lnx + l2n2x2)) = 0

Combine like terms: 1lnx + -1lnx = 0
(-1 + 0 + l2n2x2) = 0
(-1 + l2n2x2) = 0

Solving
-1 + l2n2x2 = 0

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + l2n2x2 = 0 + 1

Combine like terms: -1 + 1 = 0
0 + l2n2x2 = 0 + 1
l2n2x2 = 0 + 1

Combine like terms: 0 + 1 = 1
l2n2x2 = 1

Divide each side by 'n2x2'.
l2 = n-2x-2

Simplifying
l2 = n-2x-2

Take the square root of each side:
l = {-1n-1x-1, n-1x-1}