(log2x)/(log4x-15)=2

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Solution for (log2x)/(log4x-15)=2 equation: 


10*m-(4*m^2)+9 >= 0

(10*n-(3*m))/(m-(3*n)) = m/n

4*t = 6*(t-3.75)

6/5 = 3*v

16*m-4*m^2+9 >= 0

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