(m)3m+12=2(m-3)+4

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Solution for (m)3m+12=2(m-3)+4 equation: 



(m)3m+12=2(m-3)+4

We move all terms to the left:

(m)3m+12-(2(m-3)+4)=0



We calculate terms in parentheses: -(2(m-3)+4), so:

2(m-3)+4

We multiply parentheses

2m-6+4

We add all the numbers together, and all the variables

2m-2

Back to the equation:

-(2m-2)



We get rid of parentheses

m3m-2m+2+12=0

We add all the numbers together, and all the variables

-2m+m3m+14=0

We move all terms containing m to the left, all other terms to the right

-2m+m3m=-14

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