(m+-8)(m+17)=0

Solution for (m+-8)(m+17)=0 equation:

(m+-8)(m+17)=0

We add all the numbers together, and all the variables

(m-8)(m+17)=0

We multiply parentheses ..

(+m^2+17m-8m-136)=0

We get rid of parentheses

m^2+17m-8m-136=0

We add all the numbers together, and all the variables

m^2+9m-136=0

a = 1; b = 9; c = -136;
Δ = b2-4ac
Δ = 92-4·1·(-136)
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-25}{2*1}=\frac{-34}{2}
=-17
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+25}{2*1}=\frac{16}{2}
=8
$