(m+2)(m+3)=(m+3)(m-2)

Solution for (m+2)(m+3)=(m+3)(m-2) equation:

(m+2)(m+3)=(m+3)(m-2)

We move all terms to the left:

(m+2)(m+3)-((m+3)(m-2))=0

We multiply parentheses ..

(+m^2+3m+2m+6)-((m+3)(m-2))=0


We calculate terms in parentheses: -((m+3)(m-2)), so:

(m+3)(m-2)

We multiply parentheses ..

(+m^2-2m+3m-6)

We get rid of parentheses

m^2-2m+3m-6

We add all the numbers together, and all the variables

m^2+m-6

Back to the equation:

-(m^2+m-6)


We get rid of parentheses

m^2-m^2+3m+2m-m+6+6=0

We add all the numbers together, and all the variables

4m+12=0

We move all terms containing m to the left, all other terms to the right

4m=-12

m=-12/4

m=-3