(m+2)(m+3)=(m=2)(m-2)

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Solution for (m+2)(m+3)=(m=2)(m-2) equation: 



(m+2)(m+3)=(m=2)(m-2)

We move all terms to the left:

(m+2)(m+3)-((m)=0

We multiply parentheses ..

(+m^2+3m+2m+6)-(m=0

We get rid of parentheses

m^2+3m+2m-(m+6=0

We add all the numbers together, and all the variables

m^2+5m-(m+6=0

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