(m+2)(m+3)=m+2(m-2)

Solution for (m+2)(m+3)=m+2(m-2) equation:

(m+2)(m+3)=m+2(m-2)

We move all terms to the left:

(m+2)(m+3)-(m+2(m-2))=0

We multiply parentheses ..

(+m^2+3m+2m+6)-(m+2(m-2))=0


We calculate terms in parentheses: -(m+2(m-2)), so:

m+2(m-2)

We multiply parentheses

m+2m-4

We add all the numbers together, and all the variables

3m-4

Back to the equation:

-(3m-4)


We get rid of parentheses

m^2+3m+2m-3m+6+4=0

We add all the numbers together, and all the variables

m^2+2m+10=0

a = 1; b = 2; c = +10;
Δ = b2-4ac
Δ = 22-4·1·10
Δ = -36
Delta is less than zero, so there is no solution for the equation