(m+2)(m-2)=(m+3)(m-3)

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Solution for (m+2)(m-2)=(m+3)(m-3) equation: 



(m+2)(m-2)=(m+3)(m-3)

We move all terms to the left:

(m+2)(m-2)-((m+3)(m-3))=0

We use the square of the difference formula

m^2+m^2-4+9=0

We add all the numbers together, and all the variables

2m^2+5=0

a = 2; b = 0; c = +5;
Δ = b2-4ac
Δ = 02-4·2·5
Δ = -40
Delta is less than zero, so there is no solution for the equation

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