(m+2)(m/3)=(m/2)(m-2)

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Solution for (m+2)(m/3)=(m/2)(m-2) equation: 



(m+2)(m/3)=(m/2)(m-2)

We move all terms to the left:

(m+2)(m/3)-((m/2)(m-2))=0



Domain of the equation: 2)(m-2))!=0

m∈R



We add all the numbers together, and all the variables

(m+2)(+m/3)-((+m/2)(m-2))=0

We multiply parentheses ..

(+m^2+2m)-((+m/2)(m-2))=0

We multiply all the terms by the denominator


((+m^2+2m))*2)(m+m-2))-((=0

We add all the numbers together, and all the variables

((+m^2+2m))*2)(2m-2))-((=0

We add all the numbers together, and all the variables

((+m^2+2m))*2)(2m=0

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