(m+3)(m-4)=(m-2)(m+5)

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Solution for (m+3)(m-4)=(m-2)(m+5) equation: 



(m+3)(m-4)=(m-2)(m+5)

We move all terms to the left:

(m+3)(m-4)-((m-2)(m+5))=0

We multiply parentheses ..

(+m^2-4m+3m-12)-((m-2)(m+5))=0



We calculate terms in parentheses: -((m-2)(m+5)), so:

(m-2)(m+5)

We multiply parentheses ..

(+m^2+5m-2m-10)

We get rid of parentheses

m^2+5m-2m-10

We add all the numbers together, and all the variables

m^2+3m-10

Back to the equation:

-(m^2+3m-10)



We get rid of parentheses

m^2-m^2-4m+3m-3m-12+10=0

We add all the numbers together, and all the variables

-4m-2=0

We move all terms containing m to the left, all other terms to the right

-4m=2

m=2/-4

m=-1/2

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